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NEET CHEMISTRYMedium

4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:

A

5f > 6p > 4d > 5p

B

5f > 6p > 5p > 4d

C

6p > 5f > 5p > 4d

D

6p > 5f > 4d > 5p

Step-by-Step Solution

According to the Aufbau Principle, the energy of atomic orbitals is determined by the (n+l)(n + l) rule:

  1. Lower (n+l)(n + l) = Lower Energy.
  2. If (n+l)(n + l) is equal, the orbital with the lower nn value has lower energy.

Analysis of given orbitals:

  • 5f: n=5,l=3    (n+l)=8n=5, l=3 \implies (n+l) = 8
  • 6p: n=6,l=1    (n+l)=7n=6, l=1 \implies (n+l) = 7
  • 5p: n=5,l=1    (n+l)=6n=5, l=1 \implies (n+l) = 6
  • 4d: n=4,l=2    (n+l)=6n=4, l=2 \implies (n+l) = 6

Ordering:

  • Highest Energy: 5f5f (sum = 8)
  • Second: 6p6p (sum = 7)
  • Tie-break (5p vs 4d): Both have a sum of 6. The orbital with the higher nn (5p) has higher energy.
  • 5p>4d5p > 4d

Final Decreasing Order: 5f>6p>5p>4d5f > 6p > 5p > 4d

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