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NEET CHEMISTRYEasy

Which of the following statements is correct for a reversible process in a state of equilibrium?

A

ΔG=2.30RTlogK\Delta G = -2.30 RT \log K

B

ΔG=2.30RTlogK\Delta G = 2.30 RT \log K

C

ΔG=2.30RTlogK\Delta G^\circ = -2.30 RT \log K

D

ΔG=2.30RTlogK\Delta G^\circ = 2.30 RT \log K

Step-by-Step Solution

For a reversible process in a state of equilibrium, the change in Gibbs free energy (ΔG\Delta G) is zero. The mathematical relationship between the standard Gibbs free energy change (ΔG\Delta G^\circ) and the equilibrium constant (KK) is given by the equation: ΔG=RTlnK\Delta G^\circ = -RT \ln K. When converting the natural logarithm (ln\ln) to the base-10 logarithm (log\log), we multiply by 2.3032.303. Therefore, the equation becomes ΔG=2.303RTlogK2.30RTlogK\Delta G^\circ = -2.303 RT \log K \approx -2.30 RT \log K.

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