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NEET CHEMISTRYMedium

The pair of compounds that can exist together is:

A

FeCl3\text{FeCl}_3, SnCl2\text{SnCl}_2

B

HgCl2\text{HgCl}_2, SnCl2\text{SnCl}_2

C

FeCl2\text{FeCl}_2, SnCl2\text{SnCl}_2

D

FeCl3\text{FeCl}_3, KI\text{KI}

Step-by-Step Solution

Compounds can exist together in a solution if they do not react with each other (i.e., they do not undergo a spontaneous redox reaction).

  • FeCl3\text{FeCl}_3 and SnCl2\text{SnCl}_2: Fe3+\text{Fe}^{3+} acts as an oxidizing agent and Sn2+\text{Sn}^{2+} acts as a reducing agent, leading to a reaction: 2Fe3++Sn2+2Fe2++Sn4+2\text{Fe}^{3+} + \text{Sn}^{2+} \rightarrow 2\text{Fe}^{2+} + \text{Sn}^{4+}.
  • HgCl2\text{HgCl}_2 and SnCl2\text{SnCl}_2: Hg2+\text{Hg}^{2+} is reduced by Sn2+\text{Sn}^{2+}, causing a reaction: 2HgCl2+SnCl2Hg2Cl2+SnCl42\text{HgCl}_2 + \text{SnCl}_2 \rightarrow \text{Hg}_2\text{Cl}_2 + \text{SnCl}_4.
  • FeCl3\text{FeCl}_3 and KI\text{KI}: Fe3+\text{Fe}^{3+} oxidizes the I\text{I}^- ion to iodine gas: 2Fe3++2I2Fe2++I22\text{Fe}^{3+} + 2\text{I}^- \rightarrow 2\text{Fe}^{2+} + \text{I}_2.
  • FeCl2\text{FeCl}_2 and SnCl2\text{SnCl}_2: Both Fe2+\text{Fe}^{2+} and Sn2+\text{Sn}^{2+} are in their lower oxidation states and generally act as reducing agents. Neither is a strong enough oxidizing agent to oxidize the other. Thus, they do not react and can exist together.
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