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NEET CHEMISTRYMedium

An alkene on ozonolysis gives methanal as one of the products. Its structure is:

A

(Option 1 Structure Missing)

B

(Option 2 Structure Missing)

C

4

D

(Option 4 Structure Missing)

Step-by-Step Solution

  1. Principle of Ozonolysis: Ozonolysis is a reaction used to locate the position of a double bond in an alkene. It involves the addition of ozone (O3O_3) to the carbon-carbon double bond to form an ozonide intermediate, which is then cleaved by zinc and water (Zn/H2OZn/H_2O) to yield smaller carbonyl compounds (aldehydes or ketones) [NCERT 11th, Unit 9, Sec 9.3.5].
  2. Analysis of Products: The question states that methanal (formaldehyde, HCHOHCHO) is one of the products. Methanal is a one-carbon aldehyde. For an alkene to produce methanal upon cleavage of the double bond, the double bond must be situated at the end of the carbon chain, specifically involving a terminal methylene group (=CH2=CH_2).
  3. General Reaction: R−CH=CH2+O3→Zn/H2OR−CHO+HCHOR-CH=CH_2 + O_3 \xrightarrow{Zn/H_2O} R-CHO + HCHO
  4. Conclusion: While the specific chemical structures for the options are not visible in the text, the correct answer (Option 2) must be an alkene possessing a terminal =CH2=CH_2 group (e.g., a terminal alkene or a methylene derivative of a cyclic compound).
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