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NEET CHEMISTRYEasy

If C+O2CO2C + O_2 \rightarrow CO_2, C+12O2COC + \frac{1}{2}O_2 \rightarrow CO, and CO+12O2CO2CO + \frac{1}{2}O_2 \rightarrow CO_2, the heats of reaction are QQ, 12-12, and 10-10 respectively. Then QQ =

A

2-2

B

22

C

22-22

D

16-16

Step-by-Step Solution

According to Hess's law of constant heat summation, the enthalpy change for a reaction is the same whether it occurs in one step or in a series of steps. The overall reaction is: C+O2CO2(ΔH=Q)C + O_2 \rightarrow CO_2 \quad (\Delta H = Q) This can be obtained by adding the two intermediate steps: Step 1: C+12O2CO(ΔH1=12)C + \frac{1}{2}O_2 \rightarrow CO \quad (\Delta H_1 = -12) Step 2: CO+12O2CO2(ΔH2=10)CO + \frac{1}{2}O_2 \rightarrow CO_2 \quad (\Delta H_2 = -10) Adding Step 1 and Step 2 gives the overall reaction. Therefore, Q=ΔH1+ΔH2=12+(10)=22Q = \Delta H_1 + \Delta H_2 = -12 + (-10) = -22.

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