Which of the following compounds shall not produce propene by reaction with HBr followed by elimination or direct only elimination reaction?
A
Option 1
B
Option 2
C
4
D
Option 4
Step-by-Step Solution
Propene Formation: Propene (CH3−CH=CH2) is an alkene. Common methods to prepare alkenes include:
Dehydrohalogenation of Alkyl Halides: Alkyl halides (e.g., 1-bromopropane or 2-bromopropane) react with alcoholic KOH to eliminate HBr and form propene via β-elimination [NCERT 12th, Ch 10, Sec 10.7.1; NCERT 11th, Ch 13, Sec 13.3.4].
Dehydration of Alcohols: Alcohols (e.g., propan-1-ol or propan-2-ol) react with concentrated H2SO4 to eliminate water and form propene [NCERT 11th, Ch 13, Sec 13.3.4].
Reaction with HBr: This step typically converts an alcohol or ether into an alkyl bromide (substitution) or adds across a double bond. If the starting material is an amine (like n-propylamine), reaction with HBr forms a salt, not an alkyl halide directly suitable for simple elimination to propene in this context (amines require HNO2 for conversion to alcohols first).
Ambiguity: The specific chemical structures for the options are missing from the input data. Therefore, it is impossible to determine which specific compound fails to react. However, chemically, compounds that cannot form a 3-carbon chain with a leaving group capable of β-elimination (e.g., compounds with fewer than 3 carbons, or without β-hydrogens) would not produce propene.
Practice Mode Available
Master this Topic on Sushrut
Join thousands of students and practice with AI-generated mock tests.