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NEET Medium

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4H_2SO_4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

1

2.8

2

3.0

3

1.4

4

4.4

Step-by-Step Solution

HCOOH →Conc.H2SO4\xrightarrow{Conc. H_2SO_4} CO(g) + H2OH_2O(l). Moles of HCOOH = 2.3/46 = 1/20 mol. COOH-COOH →Conc.H2SO4\xrightarrow{Conc. H_2SO_4} CO(g) + CO2CO_2(g) + H2OH_2O(l). Moles of oxalic acid = 4.5/90 = 1/20 mol. Gaseous mixture is CO and CO2CO_2. KOH absorbs CO2CO_2. Remaining gas is CO. Total moles of CO = 1/20 + 1/20 = 2/20 mol. Weight = (2/20) * 28 = 2.8 g.

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