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NEET Hard

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: a. 60 mL M10 HCl+40 mL M10 NaOH60\text{ mL } \frac{M}{10} \text{ HCl} + 40\text{ mL } \frac{M}{10} \text{ NaOH} b. 55 mL M10 HCl+45 mL M10 NaOH55\text{ mL } \frac{M}{10} \text{ HCl} + 45\text{ mL } \frac{M}{10} \text{ NaOH} c. 75 mL M5 HCl+25 mL M5 NaOH75\text{ mL } \frac{M}{5} \text{ HCl} + 25\text{ mL } \frac{M}{5} \text{ NaOH} d. 100 mL M10 HCl+100 mL M10 NaOH100\text{ mL } \frac{M}{10} \text{ HCl} + 100\text{ mL } \frac{M}{10} \text{ NaOH} pH of which one of them will be equal to 1?

A

d

B

a

C

b

D

c

Step-by-Step Solution

For option (c): Meq of HCl = 75×15×1=1575 \times \frac{1}{5} \times 1 = 15. Meq of NaOH = 25×15×1=525 \times \frac{1}{5} \times 1 = 5. Meq of HCl in resulting solution = 15−5=1015 - 5 = 10. Molarity of [H+][H^+] in resulting mixture = 10100=110\frac{10}{100} = \frac{1}{10}. pH = −log⁡[H+]=−log⁡[110]=1.0-\log[H^+] = -\log[\frac{1}{10}] = 1.0.

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