Back to Directory
NEET Medium

The refractive index of the material of a prism is μ=2\mu = \sqrt{2} and the angle of the prism is A=30∘A = 30^\circ. One of the two refracting surfaces of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is ii.

A

30 Degree

B

45 Degree

C

60 Degree

D

Zero

Step-by-Step Solution

sin⁡isin⁡30∘=21\frac{\sin i}{\sin 30^\circ} = \frac{\sqrt{2}}{1}

⇒sin⁡i=2×12\Rightarrow \sin i = \sqrt{2} \times \frac{1}{2}

sin⁡i=12 i.e. i=45∘\sin i = \frac{1}{\sqrt{2}} \text{ i.e. } i = 45^\circ

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started