Solved: null Question for NEET

NEET Medium

Current sensitivity of a moving coil galvanometer is $5 \text{ div/mA}$ and its voltage sensitivity (angular deflection per unit voltage applied) is $20 \text{ div/V}$ . The resistance of the galvanometer is

250 $\Omega$

25 $\Omega$

40 $\Omega$

500 $\Omega$

Step-by-Step Solution

Current sensitivity $I_S = \frac{NBA}{C}$ . Voltage sensitivity $V_S = \frac{NBA}{CR_G}$ . So, resistance of galvanometer $R_G = \frac{I_S}{V_S} = \frac{5 \times 1}{20 \times 10^{-3}} = \frac{5000}{20} = 250 \text{ }\Omega$ .

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started