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An em wave is propagating in a medium with →\rightarrow a velocity v^\hat{v} V=ViV = V_i ==. The instantaneous oscillating electric field of this em wave is along +y+y axis. Then the direction of oscillating magnetic field of the em wave will be along

A

–y direction

B

+z direction

C

–z direction

D

–x direction

Step-by-Step Solution

Sol. E⃗×B⃗=V⃗\vec{E} \times \vec{B} = \vec{V}

(Ej^)×(B⃗)=Vi^(E\hat{j}) \times (\vec{B}) = V\hat{i}

So, B⃗=Bk^\vec{B} = B\hat{k}

Direction of propagation is along +z direction.

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