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Consider the following species: CN+,CN−,NO\text{CN}^+, \text{CN}^-, \text{NO} and CN\text{CN}. Which one of these will have the highest bond order?

1

CN+^+

2

CN−^-

3

NO

4

CN

Step-by-Step Solution

Bond order is calculated using molecular orbital theory. CN−\text{CN}^- has 14 electrons (bond order 3), CN\text{CN} has 13 electrons (bond order 2.5), CN+\text{CN}^+ has 12 electrons (bond order 2), and NO\text{NO} has 15 electrons (bond order 2.5). Thus, CN−\text{CN}^- has the highest bond order.

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