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NEET Easy

A carbon resistor of (47 ± 4.7) k is to be marked with rings of different colours for its identification. The colour code sequence will be

A

Yellow – Green – Violet – Gold

B

Yellow – Violet – Orange – Silver

C

Violet – Yellow – Orange – Silver

D

Green – Orange – Violet – Gold

Step-by-Step Solution

(47±4.7) kΩ=47×103±10%(47 \pm 4.7) \text{ k}\Omega = 47 \times 10^3 \pm 10\%

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