Solved: null Question for NEET

NEET Hard

The compound $C_7H_8$ undergoes the following reactions: $C_7H_8 \xrightarrow{3Cl_2/\Delta} A \xrightarrow{Br_2/Fe} B \xrightarrow{Zn/HCl} C$ . The product 'C' is

3-bromo-2,4,6-trichlorotoluene

o-bromotoluene

m-bromotoluene

p-bromotoluene

Step-by-Step Solution

Toluene ( $C_7H_8$ ) reacts with $3Cl_2/\Delta$ to form benzotrichloride. Then $Br_2/Fe$ performs electrophilic substitution at the meta position due to the deactivating $-CCl_3$ group. Finally, $Zn/HCl$ reduces $-CCl_3$ to $-CH_3$ .

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