A 40 \muF40 \text{ \mu F}40 \muF capacitor is connected to a 200 V200 \text{ V}200 V, 50 Hz50 \text{ Hz}50 Hz ac supply. The rms value of the current in the circuit is, nearly :
1.7 A1.7 \text{ A}1.7 A
2.05 A2.05 \text{ A}2.05 A
2.5 A2.5 \text{ A}2.5 A
25.1 A25.1 \text{ A}25.1 A
irms=cωϵrmsi_{\text{rms}} = c\omega \epsilon_{\text{rms}}irms=cωϵrms. Given c=40×10−6 Fc = 40 \times 10^{-6} \text{ F}c=40×10−6 F, ω=2πf=100π\omega = 2\pi f = 100\piω=2πf=100π, ϵrms=200 V\epsilon_{\text{rms}} = 200 \text{ V}ϵrms=200 V. irms=200×40×10−6×2π×50=2.5 Ai_{\text{rms}} = 200 \times 40 \times 10^{-6} \times 2\pi \times 50 = 2.5 \text{ A}irms=200×40×10−6×2π×50=2.5 A.
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