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NEET PHYSICSEasy

Two hollow conducting spheres of radii R1R_1 and R2R_2 (R1>>R2R_1 >> R_2) have equal charges. The potential would be

A

More on bigger sphere

B

More on smaller sphere

C

Equal on both the spheres

D

Dependent on the material property of the sphere

Step-by-Step Solution

Potential of a conducting hollow sphere is given by V=KQRV = \frac{KQ}{R}. Since the charge QQ is the same for both, V∝1RV \propto \frac{1}{R}. Therefore, the smaller the radius, the higher the potential. Thus, the potential is higher on the smaller sphere.

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