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Two racing cars of masses m1m_1 and m2m_2 are moving in circles of radii r1r_1 and r2r_2 respectively. Their speeds are such that each makes a complete circle in the same duration of time tt. The ratio of the angular speed of the first to the second car is:

A

m1:m2m_1:m_2

B

r1:r2r_1:r_2

C

1:11:1

D

m1r1:m2r2m_1r_1:m_2r_2

Step-by-Step Solution

In uniform circular motion, the angular speed ω\omega is defined as the angle covered per unit time. For a complete revolution (angle 2π2\pi), if the time taken is the time period TT, then the angular speed is given by ω=2πT\omega = \frac{2\pi}{T} .

Given that both cars complete the circle in the same duration of time tt, their time periods are equal (T1=T2=tT_1 = T_2 = t). Therefore, their angular speeds are: ω1=2πt\omega_1 = \frac{2\pi}{t} ω2=2πt\omega_2 = \frac{2\pi}{t}

The ratio is ω1:ω2=1:1\omega_1 : \omega_2 = 1 : 1. The angular speed is independent of the mass and radius when the time period is fixed.

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