Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Two bodies $A$ and $B$ of the same mass undergo completely inelastic one-dimensional collision. The body $A$ moves with velocity $v_1$ while the body $B$ is at rest before collision. The velocity of the system after collision is $v_2$ . The ratio of $v_1 : v_2$ is:

2:1

4:1

1:4

1:2

Step-by-Step Solution

Identify the System: A completely inelastic collision occurs when two bodies stick together after impact and move with a common velocity. Momentum is conserved, but kinetic energy is not.
Apply Conservation of Linear Momentum: $m_A v_{1i} + m_B v_{2i} = (m_A + m_B)v_f$ Given: $m_A = m_B = m$ , initial velocity of A is $v_1$ , initial velocity of B is $0$ , and final common velocity is $v_2$ . $m(v_1) + m(0) = (m + m)v_2$ $mv_1 = 2mv_2$
Calculate Ratio: $v_1 = 2v_2$ $\frac{v_1}{v_2} = \frac{2}{1}$ [Class 11 Physics, Ch 6, Sec 5.11]

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