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NEET PHYSICSMedium

Two particles AA and BB, move with constant velocities v1\vec{v}_1 and v2\vec{v}_2 respectively. At the initial moment, their position vectors are r1\vec{r}_1 and r2\vec{r}_2 respectively. The condition for particles AA and BB for their collision will be:

A

r1r2r1r2=v2v1v2v1\frac{\vec{r}_1 - \vec{r}_2}{|\vec{r}_1 - \vec{r}_2|} = \frac{\vec{v}_2 - \vec{v}_1}{|\vec{v}_2 - \vec{v}_1|}

B

r1v1=r2v2\vec{r}_1 \cdot \vec{v}_1 = \vec{r}_2 \cdot \vec{v}_2

C

r1×v1=r2×v2\vec{r}_1 \times \vec{v}_1 = \vec{r}_2 \times \vec{v}_2

D

r1r2=v1v2\vec{r}_1 - \vec{r}_2 = \vec{v}_1 - \vec{v}_2

Step-by-Step Solution

  1. Condition for Collision: For two particles to collide, they must occupy the same position at the same instant of time tt (t>0t > 0).
  2. Position Equations:
  • Position of particle A at time tt: rA(t)=r1+v1t\vec{r}_A(t) = \vec{r}_1 + \vec{v}_1 t
  • Position of particle B at time tt: rB(t)=r2+v2t\vec{r}_B(t) = \vec{r}_2 + \vec{v}_2 t
  1. Equating Positions: r1+v1t=r2+v2t\vec{r}_1 + \vec{v}_1 t = \vec{r}_2 + \vec{v}_2 t r1r2=(v2v1)t\vec{r}_1 - \vec{r}_2 = (\vec{v}_2 - \vec{v}_1) t
  2. Direction Analysis: The equation implies that the relative displacement vector (r1r2)(\vec{r}_1 - \vec{r}_2) is parallel to the relative velocity vector (v2v1)(\vec{v}_2 - \vec{v}_1). Since time tt must be positive for a future collision, these two vectors must point in the same direction.
  3. Unit Vectors: If two vectors are in the same direction, their unit vectors must be equal . r^relative=v^relative\hat{r}_{relative} = \hat{v}_{relative} r1r2r1r2=v2v1v2v1\frac{\vec{r}_1 - \vec{r}_2}{|\vec{r}_1 - \vec{r}_2|} = \frac{\vec{v}_2 - \vec{v}_1}{|\vec{v}_2 - \vec{v}_1|}
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