Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

Let a wire be suspended from the ceiling (rigid support) and stretched by a weight $W$ attached at its free end. The longitudinal stress at any point of the cross-sectional area $A$ of the wire is:

zero

$\frac{2W}{A}$

$\frac{W}{A}$

$\frac{W}{2A}$

Step-by-Step Solution

Definition of Stress: Longitudinal stress is defined as the internal restoring force ( $F$ ) developed per unit cross-sectional area ( $A$ ) of a body when it is subjected to a deforming force. $\text{Stress} (\sigma) = \frac{\text{Restoring Force} (F)}{\text{Area} (A)}$
Force Analysis: When a weight $W$ is suspended from the free end of the wire, the wire stretches. In a state of equilibrium, the internal restoring force (tension) developed in the wire is equal in magnitude to the external deforming force (the weight $W$ ). $F = W$
Calculation: Substituting the force into the stress formula: $\text{Longitudinal Stress} = \frac{W}{A}$

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started