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NEET PHYSICSMedium

A wave in a string has an amplitude of 2 cm2 \text{ cm}. The wave travels in the positive direction of the x-axis with a speed of 128 m/s128 \text{ m/s} and it is noted that 55 complete waves fit in the 4 m4 \text{ m} length of the string. The equation describing the wave is:

A

y=(0.02 m)sin(7.85x+1005t)y=(0.02 \text{ m})\sin(7.85x+1005t)

B

y=(0.02 m)sin(15.7x2010t)y=(0.02 \text{ m})\sin(15.7x-2010t)

C

y=(0.02 m)sin(15.7x+2010t)y=(0.02 \text{ m})\sin(15.7x+2010t)

D

y=(0.02 m)sin(7.85x1005t)y=(0.02 \text{ m})\sin(7.85x-1005t)

Step-by-Step Solution

Given: Amplitude, A=2 cm=0.02 mA = 2 \text{ cm} = 0.02 \text{ m} Velocity of wave, v=128 m/sv = 128 \text{ m/s} 55 complete waves fit in a 4 m4 \text{ m} length. Therefore, the wavelength λ\lambda is: λ=45=0.8 m\lambda = \frac{4}{5} = 0.8 \text{ m} The wave number kk is calculated as: k=2πλ=2×3.140.8=7.85 m1k = \frac{2\pi}{\lambda} = \frac{2 \times 3.14}{0.8} = 7.85 \text{ m}^{-1} The angular frequency ω\omega is calculated using the relation v=ωkv = \frac{\omega}{k}: ω=v×k=128×7.85=1004.81005 rad/s\omega = v \times k = 128 \times 7.85 = 1004.8 \approx 1005 \text{ rad/s} Since the wave is traveling in the positive x-direction, the general equation of the wave is of the form: y=Asin(kxωt)y = A \sin(kx - \omega t) Substituting the derived values: y=(0.02 m)sin(7.85x1005t)y = (0.02 \text{ m}) \sin(7.85x - 1005t)

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