Back to Directory
NEET PHYSICSMedium

The quantities of heat required to raise the temperature of two solid copper spheres of radii r1r_1 and r2r_2 (r1=1.5r2r_1=1.5 r_2) through 1 K1\text{ K} are in the ratio:

A

94\frac{9}{4}

B

32\frac{3}{2}

C

53\frac{5}{3}

D

278\frac{27}{8}

Step-by-Step Solution

The quantity of heat required to raise the temperature of a body is given by ΔQ=mcΔT\Delta Q = mc\Delta T. The mass of a solid sphere is m=Volume×Density=43πr3ρm = \text{Volume} \times \text{Density} = \frac{4}{3}\pi r^3 \rho. Therefore, ΔQ=43πr3ρcΔT\Delta Q = \frac{4}{3}\pi r^3 \rho c \Delta T. For both copper spheres, the density ρ\rho, specific heat capacity cc, and the change in temperature ΔT\Delta T (1 K1\text{ K}) are the same. Thus, the heat required is directly proportional to the cube of the radius: ΔQr3\Delta Q \propto r^3. The ratio of the quantities of heat required is: ΔQ1ΔQ2=(r1r2)3\frac{\Delta Q_1}{\Delta Q_2} = \left(\frac{r_1}{r_2}\right)^3 Given r1=1.5r2=32r2r_1 = 1.5 r_2 = \frac{3}{2} r_2, we have r1r2=32\frac{r_1}{r_2} = \frac{3}{2}. Substituting this value: ΔQ1ΔQ2=(32)3=278\frac{\Delta Q_1}{\Delta Q_2} = \left(\frac{3}{2}\right)^3 = \frac{27}{8}

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut