Solved: Physics Question for NEET

NEET PhysicsEasy

The average thermal energy for a mono-atomic gas is : ( $k_B$ is Boltzmann constant and T, absolute temperature)

$\frac{1}{2} k_B T$

$\frac{3}{2} k_B T$

$\frac{5}{2} k_B T$

$\frac{7}{2} k_B T$

For monoatomic gases, degree of freedom is 3. Hence average thermal energy per molecule is $KE_{avg} = \frac{3}{2} k_B T$ .

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