In pure rolling motion, the velocity of any point on the wheel is the vector sum of the translational velocity of the center of mass ($v$) and the tangential velocity due to rotation ($\omega R$). For a wheel of radius $R$ rolling without slipping, the condition is $v = \omega R$. At the highest point $P$, the translational velocity and rotational velocity are in the same direction. So, the net speed is $v_P = v + \omega R = v + v = 2v$. At the lowest point $Q$ (point of contact with the ground), the translational velocity and rotational velocity are in opposite directions. So, the net speed is $v_Q = v - \omega R = v - v = 0$. Therefore, point $P$ moves with a speed of $2v$, while point $Q$ is instantaneously at rest (speed is zero). Thus, point $P$ moves faster than point $Q$.