Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A packet is dropped from a balloon which is going upwards with the velocity $12 \text{ m/s}$ , the velocity of the packet after $2 \text{ seconds}$ will be:

–12 m/s

12 m/s

–7.6 m/s

7.6 m/s

Step-by-Step Solution

Identify Initial Conditions: When an object is dropped from a moving body (like a balloon), it inherits the velocity of that body at the instant of release.

Initial velocity of the packet, $u = +12 \text{ m/s}$ (taking upward direction as positive).

Identify Acceleration: The packet is under the influence of gravity.

Acceleration, $a = -g = -9.8 \text{ m/s}^2$ (acting downwards).

Apply Kinematic Equation: To find the final velocity ( $v$ ) after time $t = 2 \text{ s}$ , use the first equation of motion: $v = u + at$ $v = 12 + (-9.8)(2)$ $v = 12 - 19.6$ $v = -7.6 \text{ m/s}$ The negative sign indicates that the packet is moving downwards with a speed of $7.6 \text{ m/s}$ .

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