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NEET PHYSICSEasy

The dimensions of Planck's constant and angular momentum are respectively:

A

ML2T1ML^2 T^{-1} and MLT1MLT^{-1}

B

ML2T1ML^2 T^{-1} and ML2T1ML^2 T^{-1}

C

MLT1MLT^{-1} and ML2T1ML^2 T^{-1}

D

MLT1MLT^{-1} and ML2T2ML^2 T^{-2}

Step-by-Step Solution

To find the dimensions of Planck's constant and angular momentum, we examine their defining equations:

  1. Planck's Constant (hh): According to Planck's quantum theory, the energy (EE) of a quantum of radiation is given by E=hνE = h\nu, where ν\nu is the frequency . From the sources, energy has the dimensions [ML2T2][ML^2T^{-2}] and frequency has the dimension [T1][T^{-1}] . Therefore, the dimensions of hh are [ML2T2]/[T1]=[ML2T1][ML^2T^{-2}] / [T^{-1}] = [ML^2T^{-1}] .

  2. Angular Momentum (LL): Angular momentum is defined as the product of mass (mm), velocity (vv), and radius (rr), expressed as L=mvrL = mvr . Mass has the dimension [M][M], velocity has dimensions [LT1][LT^{-1}], and radius has the dimension [L][L]. Thus, the dimensions of angular momentum are [M]×[LT1]×[L]=[ML2T1][M] \times [LT^{-1}] \times [L] = [ML^2T^{-1}] .

Since both physical quantities share the same dimensional formula, the correct pair is [ML2T1][ML^2 T^{-1}] and [ML2T1][ML^2 T^{-1}], which corresponds to Option B.

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