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An electron having charge e and mass m is moving in a uniform electric field E. Its acceleration will be:

A

e²/2m

B

E²/2m

C

eE/m

D

mE/e

Step-by-Step Solution

The electric force F\mathbf{F} experienced by a charge qq in a uniform electric field E\mathbf{E} is given by F=qE\mathbf{F} = q\mathbf{E}. For an electron, the magnitude of the force is F=eEF = eE. According to Newton's second law of motion, the force is also equal to the product of mass and acceleration (F=maF = ma). Equating the two expressions for force (ma=eEma = eE), the acceleration aa is given by a=eEma = \frac{eE}{m} . This acceleration is constant and directed opposite to the electric field for a negatively charged particle like an electron.

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