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Two non-mixing liquids of densities ρ\rho and nρn\rho (n>1n>1) are put in a container. The height of each liquid is hh. A solid cylinder floats with its axis vertical and length LL. The length of the cylinder inside the denser liquid is pLpL (p<1p<1). The density of the cylinder is dd. The density dd is equal to:

A

[2+(n+1)p]ρ[2+(n+1)p]\rho

B

[2+(n1)p]ρ[2+(n-1)p]\rho

C

[1+(n1)p]ρ[1+(n-1)p]\rho

D

[1+(n+1)p]ρ[1+(n+1)p]\rho

Step-by-Step Solution

  1. Principle of Floatation: For a body floating in a fluid (or multiple fluids), the total weight of the body is equal to the total buoyant force (upthrust) exerted by the displaced fluids .
  2. Weight of Cylinder: Let AA be the cross-sectional area of the cylinder. The volume of the cylinder is V=ALV = AL. The weight of the cylinder is W=mg=(ALd)gW = mg = (ALd)g.
  3. Buoyant Force: The cylinder is partially immersed in the denser liquid (density nρn\rho) and partially in the lighter liquid (density ρ\rho).
  • Volume in denser liquid: V1=A(pL)V_1 = A(pL).
  • Volume in lighter liquid: Since the total length is LL, the remaining length is (LpL)=L(1p)(L - pL) = L(1-p). Thus, V2=AL(1p)V_2 = A L (1-p).
  • Total Buoyant Force (FBF_B) = Weight of displaced denser liquid + Weight of displaced lighter liquid. FB=(V1nρg)+(V2ρg)F_B = (V_1 \cdot n\rho \cdot g) + (V_2 \cdot \rho \cdot g) FB=A(pL)(nρ)g+AL(1p)(ρ)gF_B = A(pL)(n\rho)g + A L (1-p)(\rho)g
  1. Equilibrium Equation: W=FBW = F_B ALdg=ALpnρg+AL(1p)ρgALdg = ALpn\rho g + AL(1-p)\rho g Divide by ALgALg: d=pnρ+(1p)ρd = pn\rho + (1-p)\rho d=ρ[pn+1p]d = \rho [pn + 1 - p] d=ρ[1+p(n1)]d = \rho [1 + p(n - 1)] d=[1+(n1)p]ρd = [1 + (n-1)p]\rho
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