Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A truck and a car are moving with equal velocity. If equal retarding force is applied on each, then on applying the brakes both will stop after certain distance:

Truck will cover less distance before rest

Car will cover less distance before rest

Both will cover equal distance

None

Step-by-Step Solution

Analyze using Work-Energy Theorem: The work done by the retarding force ( $F$ ) in stopping the vehicle over a distance ( $s$ ) is equal to the initial kinetic energy ( $K$ ) of the vehicle. $W = F \cdot s = K = \frac{1}{2}mv^2$ [Source 144]
Derive Relationship: Rearranging for distance $s$ : $s = \frac{mv^2}{2F}$
Compare Variables:

Initial velocity ( $v$ ) is the same for both.
Retarding force ( $F$ ) is the same for both.
Therefore, the stopping distance is directly proportional to the mass: $s \propto m$ .

Conclusion: Since the mass of the truck ( $m_{truck}$ ) is greater than the mass of the car ( $m_{car}$ ), the stopping distance for the truck will be greater ( $s_{truck} > s_{car}$ ). Consequently, the car will cover less distance before coming to rest.

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