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The period of oscillation of a mass MM suspended from a spring of negligible mass is TT. If along with it another mass MM is also suspended, the period of oscillation will now be:

A

TT

B

T/2T/\sqrt{2}

C

2T2T

D

2T\sqrt{2}T

Step-by-Step Solution

The time period (TT) of a spring-mass system oscillating in Simple Harmonic Motion (SHM) is derived from the restoring force F=kxF = -kx . The period is given by the formula: T=2πmkT = 2\pi \sqrt{\frac{m}{k}} where mm is the mass and kk is the spring constant.

  1. Initial Condition: With mass MM, the period is: T=2πMkT = 2\pi \sqrt{\frac{M}{k}}

  2. New Condition: When another mass MM is suspended along with the first, the total mass becomes m=M+M=2Mm' = M + M = 2M. The new period TT' is: T=2π2MkT' = 2\pi \sqrt{\frac{2M}{k}}

  3. Comparison: T=2(2πMk)=2TT' = \sqrt{2} \left( 2\pi \sqrt{\frac{M}{k}} \right) = \sqrt{2}T

Therefore, the new period of oscillation is 2T\sqrt{2}T.

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