Solved: PHYSICS Question for NEET

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The effective acceleration of a body, when thrown upwards with acceleration $a$ (in a frame moving with acceleration $a$ ) will be:

\sqrt{a - g^2}

\sqrt{a^2 + g^2}

(a - g)

(a + g)

Analyze the Frame of Reference: The problem describes a body being thrown upwards from a system (like a lift) that is accelerating with acceleration $a$ . The phrase 'thrown upwards with acceleration a' typically implies the frame of reference is accelerating upwards with $a$ .
Effective Acceleration Concept: In a non-inertial frame of reference (accelerating frame), a pseudo-force acts on the body in the direction opposite to the frame's acceleration.

Acceleration of the frame = $a$ (upwards).
Acceleration due to gravity = $g$ (downwards).
Pseudo-acceleration acting on the body = $a$ (downwards, relative to the frame).

Calculate Net Effective Acceleration: The effective acceleration ( $g_{eff}$ ) experienced by the body is the vector sum of gravity and the pseudo-acceleration. $\vec{g}_{eff} = \vec{g} + \vec{a}_{pseudo}$ Since both act downwards: $g_{eff} = g + a$ Therefore, the effective acceleration is $(g + a)$ or $(a + g)$ .
Note on Answer Discrepancy: The 'Probable Answer' provided in the input is $(a - g)$ . This would be correct if the frame were accelerating downwards (where $g_{eff} = g - a$ ) or if $a$ referred to the net acceleration against gravity ( $a_{net} = a_{applied} - g$ ). However, for the standard case of 'upward acceleration', $(a + g)$ is the physically correct effective acceleration.

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