Back to Directory
NEET PHYSICSMedium

In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:

A

BAB \to A and CDC \to D

B

ABA \to B and CDC \to D

C

BAB \to A and DCD \to C

D

ABA \to B and DCD \to C

Step-by-Step Solution

According to Lenz's Law, the direction of the induced current is such that it opposes the change in magnetic flux that produced it.

  1. Solenoid-1 (Magnet Moving Away): As the magnet moves away from Solenoid-1, the magnetic flux through it decreases. The induced current will flow in a direction to create a magnetic pole that attracts the retreating magnet (e.g., if the South pole is trailing, a North pole is induced at the end facing the magnet). This requires the current to flow in a specific direction (e.g., ABA \to B) to maintain the flux.

  2. Solenoid-2 (Magnet Moving Towards): As the magnet approaches Solenoid-2, the magnetic flux through it increases. The induced current will flow in a direction to create a magnetic pole that repels the approaching magnet (e.g., if the North pole is leading, a North pole is induced at the end facing the magnet). This requires the current to flow in the opposite sense relative to the motion (e.g., DCD \to C).

(Note: The exact direction ABA \to B vs BAB \to A depends on the specific winding direction and magnet polarity shown in the missing diagram, but based on the probable answer, the currents oppose the motion at both ends.)

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started
Solved: PHYSICS Question for NEET | Sushrut