Back to Directory
NEET PHYSICSEasy

Two copper vessels A and B have the same base area but are of different shapes. A takes twice the volume of water that B requires to fill up to a particular common height. Then the correct statement among the following is:

A

pressure on the base area of vessels A and B is the same.

B

pressure on the base area of vessels A and B is not the same.

C

both vessels A and B weigh the same.

D

vessel B weighs twice that of A.

Step-by-Step Solution

The pressure exerted by a liquid at the base of a container is given by the formula P=Patm+ρghP = P_{atm} + \rho g h, where ρ\rho is the density of the liquid, gg is the acceleration due to gravity, and hh is the height of the liquid column .

  1. Dependency: The formula shows that pressure depends only on the vertical height (hh) and the density of the fluid (ρ\rho). It is independent of the shape of the vessel or the total volume/mass of the liquid contained .
  2. Application: Since both vessels A and B are filled with the same liquid (water) to the same vertical height (hh), the pressure at the base of both vessels is identical.
  3. Hydrostatic Paradox: This counter-intuitive result, where pressure is independent of the volume or shape, is known as the hydrostatic paradox .

Note: While the pressures are equal, the thrust (Force = Pressure ×\times Area) on the base would also be the same because the base areas are equal. However, the total weight of the liquid would differ because the volumes differ.

Practice Mode Available

Master this Topic on Sushrut

Join thousands of students and practice with AI-generated mock tests.

Get Started