Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

The tension in the string revolving in a vertical circle with a mass $m$ at the end which is at the lowest position is:

$\frac{mv^2}{r}$

$\frac{mv^2}{r} - mg$

$\frac{mv^2}{r} + mg$

$mg$

Identify Forces: At the lowest point of a vertical circle, the forces acting on the mass $m$ are the tension ( $T$ ) in the string acting upwards (towards the center) and the gravitational force ( $mg$ ) acting vertically downwards.
Newton's Second Law: The net radial force towards the center provides the necessary centripetal force ( $F_c = \frac{mv^2}{r}$ ) to maintain the circular path. $F_{net} = T - mg$
Equation of Motion: Equating the net force to the centripetal force: $T - mg = \frac{mv^2}{r}$
Solve for Tension: $T = \frac{mv^2}{r} + mg$ [Source 75]

Practice Mode Available

Join thousands of students and practice with AI-generated mock tests.