The magnetic energy stored in an inductor of inductance 4μH4 \mu\text{H}4μH carrying a current of 2A2 \text{A}2A is
4μJ4 \mu\text{J}4μJ
4mJ4 \text{mJ}4mJ
8mJ8 \text{mJ}8mJ
8μJ8 \mu\text{J}8μJ
The magnetic energy UUU stored in an inductor is given by U=12LI2U = \frac{1}{2}LI^2U=21LI2. Given L=4μH=4×10−6HL = 4 \mu\text{H} = 4 \times 10^{-6} \text{H}L=4μH=4×10−6H and I=2AI = 2 \text{A}I=2A. Thus, U=12×(4×10−6)×(2)2=2×10−6×4=8×10−6J=8μJU = \frac{1}{2} \times (4 \times 10^{-6}) \times (2)^2 = 2 \times 10^{-6} \times 4 = 8 \times 10^{-6} \text{J} = 8 \mu\text{J}U=21×(4×10−6)×(2)2=2×10−6×4=8×10−6J=8μJ.
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