The rate of heat flow through a rod by conduction is given by $H = \frac{\Delta Q}{\Delta t} = \frac{KA\Delta T}{L}$, where $K$ is the thermal conductivity, $A$ is the cross-sectional area, $L$ is the length, and $\Delta T$ is the temperature difference between the ends. In the first case, $\Delta T_1 = 110 ^\circ\text{C} - 100 ^\circ\text{C} = 10 ^\circ\text{C}$. The rate of heat flow is $H_1 = 4.0 \text{ J/s}$. In the second case, $\Delta T_2 = 210 ^\circ\text{C} - 200 ^\circ\text{C} = 10 ^\circ\text{C}$. Since the temperature difference $\Delta T$ is the same in both cases and the dimensions and material of the rod remain unchanged, the rate of heat flow will be the same (assuming the thermal conductivity $K$ is essentially constant over this temperature range). Therefore, $H_2 = H_1 = 4.0 \text{ J/s}$.