Solved: PHYSICS Question for NEET | Sushrut

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NEET PHYSICSEasy

A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m/s², the velocity with which it hits the ground will be:

A

20 m/s

B

40 m/s

C

5 m/s

D

10 m/s

Step-by-Step Solution

Identify Given Values: Initial velocity ( $u$ ) = 0 (dropped from rest). Displacement ( $h$ ) = 20 m.

Acceleration due to gravity ( $g$ ) = 10 m/s².

Select Kinematic Equation: Use the third equation of motion connecting velocity, displacement, and acceleration: $v^2 = u^2 + 2gh$
Calculation: $v^2 = (0)^2 + 2(10)(20)$ $v^2 = 400$ $v = \sqrt{400} = 20 \text{ m/s}$

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Solved: PHYSICS Question for NEET | Sushrut