Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A ball is projected with velocity $v_0$ at an angle of elevation $30^{\circ}$ . Mark the correct statement.

Kinetic energy will be zero at the highest point of the trajectory.

Vertical component of momentum will be conserved.

Horizontal component of momentum will be conserved.

Gravitational potential energy will be minimum at the highest point of the trajectory.

Horizontal Motion: In projectile motion (neglecting air resistance), there is no force acting on the particle in the horizontal direction ( $F_x = 0$ ). According to Newton's Second Law, if the net force is zero, momentum is conserved. Since acceleration $a_x = 0$ , the horizontal velocity $v_x$ remains constant, and thus the horizontal component of momentum ( $p_x = mv_x$ ) is conserved .
Vertical Motion: A constant force of gravity acts downwards, causing the vertical velocity component to change continuously. Thus, the vertical component of momentum is not conserved.
Energy Analysis: At the highest point, the vertical velocity is zero, but the horizontal velocity is non-zero ( $v_x = v_0 \cos 30^{\circ}$ ). Therefore, kinetic energy is not zero . At the highest point, the height is maximum, so the gravitational potential energy ( $mgh$ ) is maximum, not minimum.

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