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NEET PHYSICSMedium

A black body at 1227C1227^\circ\text{C} emits radiations with maximum intensity at a wavelength of 5000 A˚5000 \text{ \AA}. If the temperature of the body is increased by 1000C1000^\circ\text{C}, the maximum intensity will be observed at:

A

4000 A˚4000 \text{ \AA}

B

5000 A˚5000 \text{ \AA}

C

6000 A˚6000 \text{ \AA}

D

3000 A˚3000 \text{ \AA}

Step-by-Step Solution

According to Wien's displacement law, the product of the wavelength corresponding to maximum intensity (λm\lambda_m) and the absolute temperature (TT) is constant: λmT=constant\lambda_m T = \text{constant}. Given initial temperature, T1=1227C=1227+273=1500 KT_1 = 1227^\circ\text{C} = 1227 + 273 = 1500 \text{ K}. Initial wavelength, λ1=5000 A˚\lambda_1 = 5000 \text{ \AA}. The temperature is increased by 1000C1000^\circ\text{C}, so the new absolute temperature is T2=1500 K+1000 K=2500 KT_2 = 1500 \text{ K} + 1000 \text{ K} = 2500 \text{ K}. Using the relation λ1T1=λ2T2\lambda_1 T_1 = \lambda_2 T_2: λ2=λ1T1T2=5000×15002500=2×1500=3000 A˚\lambda_2 = \frac{\lambda_1 T_1}{T_2} = \frac{5000 \times 1500}{2500} = 2 \times 1500 = 3000 \text{ \AA}.

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