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A coil of resistance 400Ω400\Omega is placed in a magnetic field. If the magnetic flux ϕ  (Wb)\phi\;(\text{Wb}) linked with the coil varies with time t  (sec)t\;(\text{sec}) as ϕ=50t2+4\phi=50t^2+4. The current in the coil at t=2st=2\text{s} is:

A

0.5A

B

0.1A

C

2A

D

1A

Step-by-Step Solution

According to Faraday's Law of Induction, the magnitude of the induced electromotive force (ε|\varepsilon|) is equal to the rate of change of magnetic flux (ϕ\phi) .

  1. Calculate Induced EMF (ε|\varepsilon|): ε=dϕdt|\varepsilon| = \left| \frac{d\phi}{dt} \right| Given ϕ=50t2+4\phi = 50t^2 + 4, differentiating with respect to time tt: dϕdt=ddt(50t2+4)=100t\frac{d\phi}{dt} = \frac{d}{dt}(50t^2 + 4) = 100t At t=2st = 2\text{s}: ε=100(2)=200 V|\varepsilon| = 100(2) = 200 \text{ V}

  2. Calculate Induced Current (II): Using Ohm's Law (I=VRI = \frac{V}{R}), where V=εV = |\varepsilon| and RR is the resistance : I=εR=200 V400ΩI = \frac{|\varepsilon|}{R} = \frac{200 \text{ V}}{400 \Omega} I=0.5 AI = 0.5 \text{ A}

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