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An iron rod of susceptibility 599 is subjected to a magnetising field of 1200Am11200 A m^{-1}. The permeability of the material of the rod is : (μ0=4π×107TmA1\mu_0 = 4\pi \times 10^{-7} T m A^{-1})

1

2.4π×104TmA12.4\pi \times 10^{-4} T m A^{-1}

2

8.0×105TmA18.0 \times 10^{-5} T m A^{-1}

3

2.4π×105TmA12.4\pi \times 10^{-5} T m A^{-1}

4

2.4π×107TmA12.4\pi \times 10^{-7} T m A^{-1}

Step-by-Step Solution

μr=1+χm=1+599=600\mu_r = 1 + \chi_m = 1 + 599 = 600. μ=μ0μr=4π×107×600=2400π×107=2.4π×104TmA1\mu = \mu_0 \mu_r = 4\pi \times 10^{-7} \times 600 = 2400\pi \times 10^{-7} = 2.4\pi \times 10^{-4} T m A^{-1}

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