Solved: PHYSICS Question for NEET

NEET PHYSICSEasy

A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: (Take 1/4\pi ε₀ = 9 × 10⁹ SI units)

1 × 10⁵

0.5 × 10⁵

zero

3 × 10⁵

Step-by-Step Solution

Electric Field Inside a Shell: For a uniformly charged thin spherical shell, the electric field inside the shell is zero everywhere. This is analogous to the gravitational field inside a spherical shell of uniform density being zero, as discussed in classical mechanics [1].
Relation to Potential: The electric field ( $E$ ) is related to the electric potential ( $V$ ) by the gradient relationship $E = -dV/dr$ . Since $E = 0$ inside the shell, the change in potential ( $dV$ ) is zero.
Constant Potential: This implies that the electric potential is constant throughout the interior of the shell and is equal to the potential at the surface.
Conclusion: Since both points $C$ (presumably the center) and $P$ (a point inside) are within the interior region where potential is constant, the potential difference between them is zero ( $V_C - V_P = 0$ ).

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