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NEET PHYSICSMedium

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is :

A

Mgl

B

MgL

C

\frac{1}{2}Mgl

D

\frac{1}{2}MgL

Step-by-Step Solution

The work done by gravity is U=12MglU = \frac{1}{2}Mgl. This work is stored as elastic potential energy in the wire.

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