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NEET PHYSICSMedium

The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration in rad/s2\text{rad/s}^2 is

A

2 π\pi

B

4 π\pi

C

12 π\pi

D

104 π\pi

Step-by-Step Solution

Angular acceleration α=Δωt\alpha = \frac{\Delta \omega}{t}. Initial angular velocity ω1=1200×2π60 rad/s\omega_1 = 1200 \times \frac{2\pi}{60} \text{ rad/s}. Final angular velocity ω2=3120×2π60 rad/s\omega_2 = 3120 \times \frac{2\pi}{60} \text{ rad/s}. α=(3120−1200)16×2π60=4π rad/s2\alpha = \frac{(3120 - 1200)}{16} \times \frac{2\pi}{60} = 4\pi \text{ rad/s}^2.

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