Let the particle of mass $m_1 = 5 \text{ kg}$ be placed at the origin, so its position coordinate is $x_1 = 0$. The particle of mass $m_2 = 10 \text{ kg}$ is at a distance of $1 \text{ m} = 100 \text{ cm}$, so its position coordinate is $x_2 = 100 \text{ cm}$. The position of the centre of mass from the $5 \text{ kg}$ particle is given by: $X_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2}$ $X_{cm} = \frac{5(0) + 10(100)}{5 + 10}$ $X_{cm} = \frac{1000}{15} = \frac{200}{3} \text{ cm} \approx 66.67 \text{ cm}$ Therefore, the centre of mass of the system from the $5 \text{ kg}$ particle is nearly at a distance of $67 \text{ cm}$.