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NEET PHYSICSEasy

A body of mass 60 g60\text{ g} experiences a gravitational force of 3.0 N3.0\text{ N}, when placed at a particular point. The magnitude of the gravitational field intensity at that point is

A

0.05 N/kg0.05\text{ N/kg}

B

50 N/kg50\text{ N/kg}

C

20 N/kg20\text{ N/kg}

D

180 N/kg180\text{ N/kg}

Step-by-Step Solution

The gravitational force FF is given by F=mEGF = m E_G, where mm is mass and EGE_G is gravitational field intensity. Converting mass to kg: m=60 g=0.06 kgm = 60\text{ g} = 0.06\text{ kg}. Thus, 3.0=0.06×EG3.0 = 0.06 \times E_G, which gives EG=3.00.06=50 N/kgE_G = \frac{3.0}{0.06} = 50\text{ N/kg}.

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