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NEET PHYSICSMedium

In a series LCR circuit, the inductance LL is 10 mH, capacitance CC is 1 μ\muF and resistance RR is 100 Ω\Omega. The frequency at which resonance occurs is:

A

1.59 kHz

B

15.9 rad/s

C

15.9 kHz

D

1.59 rad/s

Step-by-Step Solution

In a series LCR circuit, resonance occurs when the inductive reactance equals the capacitive reactance (XL=XCX_L = X_C). The resonant angular frequency is defined as ω0=1/LC\omega_0 = 1/\sqrt{LC} . The resonant frequency in Hertz is calculated using the formula ν0=12πLC\nu_0 = \frac{1}{2\pi\sqrt{LC}} . Given L=10 mH=102 HL = 10 \text{ mH} = 10^{-2} \text{ H} and C=1 \muF=106 FC = 1 \text{ \mu F} = 10^{-6} \text{ F}, we have: ν0=12π102×106=12π108=12π×104=100002π100006.2831591.5 Hz\nu_0 = \frac{1}{2\pi\sqrt{10^{-2} \times 10^{-6}}} = \frac{1}{2\pi\sqrt{10^{-8}}} = \frac{1}{2\pi \times 10^{-4}} = \frac{10000}{2\pi} \approx \frac{10000}{6.283} \approx 1591.5 \text{ Hz}, which is approximately 1.59 kHz.

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