The volume of a sphere is given by the formula $V = \frac{4}{3}\pi r^3$. The maximum percentage error in the volume is related to the percentage error in the radius by the formula: $\frac{\Delta V}{V} \times 100 = 3 \times \left(\frac{\Delta r}{r} \times 100\right)$ Given that the percentage error in the measurement of the radius is $\frac{\Delta r}{r} \times 100 = 2\%$, we can substitute this value into the equation: $\% \text{ error in } V = 3 \times 2\% = 6\%$.