Since the circuit diagram is missing in the question, we can deduce its structure from the provided correct answer for this standard NEET 2016 problem. The circuit typically consists of an OR gate taking inputs A and B, and an AND gate taking the output of the OR gate along with the third input C. The Boolean expression for this circuit is $Y = (A + B) \cdot C$. To get a high output ($Y = 1$), the AND gate requires both of its inputs to be 1. Therefore, input $C$ must be 1, and the output of the OR gate $(A + B)$ must be 1. Testing the given options: Option A: $Y = (1 + 0) \cdot 0 = 0$ Option B: $Y = (1 + 1) \cdot 0 = 0$ Option C: $Y = (1 + 0) \cdot 1 = 1 \cdot 1 = 1$ Option D: $Y = (0 + 1) \cdot 0 = 0$ Thus, the correct choice is A = 1, B = 0, C = 1.