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A radioactive nucleus ZAX{}_Z^A X undergoes spontaneous decay in the sequence ZAX→Z−1B→Z−3C→Z−2D{}_Z^A X \to {}_{Z-1} B \to {}_{Z-3} C \to {}_{Z-2} D, where ZZ is the atomic number of element XX. The possible decay particles in the sequence are

A

α,β−,β+\alpha, \beta^-, \beta^+

B

α,β+,β−\alpha, \beta^+, \beta^-

C

β+,α,β−\beta^+, \alpha, \beta^-

D

β−,α,β+\beta^-, \alpha, \beta^+

Step-by-Step Solution

On β+\beta^+ decay atomic number decreases by 1. On β−\beta^- decay atomic number increases by 1. On α\alpha decay atomic number decreases by 2. The sequence is ZAX→β+ decayZ−1B→α decayZ−3C→β− decayZ−2D{}_Z^A X \xrightarrow{\beta^+ \text{ decay}} {}_{Z-1} B \xrightarrow{\alpha \text{ decay}} {}_{Z-3} C \xrightarrow{\beta^- \text{ decay}} {}_{Z-2} D. Hence correct order of decay are β+,α,β−\beta^+, \alpha, \beta^-.

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